Based on Sybase Administration guide, suppose my sybase has 2K logical pages, 8MB are allocated to the default data cache. This constitutes approximately 2048 buffers. so it means the buffer number is 8*1204K/(2K*2) = 2048. this means buffer size is 4K or 2*page size.
Is it right?
Also if data cache is configured as above said 8M, then "Number of sort buffers" should be set at least as 2048, right?